Happy Birthday to Me
So, its my 23rd birthday, here are my thoughts on the occasion
[ Here p(n) is the nth prime ]
- 2*(2+3)*2 + 3 = 23
- 2*(2+3) + 32 = 19
- (2*3) + p(2*3) = 19
- (2/3) + (1/9) = ( p(22) / 32 )
- (2/3) - (1/9) = p(3)/32
- 2*3 + 1*9 = (2+3)*3
- 1*9 - 2*3 = 3
- (2*3)/(1*9) = 2/3
- (2+3)/(1+9) = 1/2
- (2*3)/(1+9) = p(2)/p(3)
- 22 + 32 = p(2*3)
- 23 + 33 = p(22)*p(3)
- 33 - 23 = 19
- 23 + 32 = p(22 + 3) = p(32 - 2)
- √2 + √3 = 3.14
- 9 - 1 = 23
- 12 + 92 = 2*p(p(2*3))
- (p-1(19)+1)3 + (p-1(23)+1)3 = 1729
- 1901 = p(22*p(2*p(p(p(2))) - 1) - 1)
No, this is too much. Something is surely wrong with me.